Base | Representation |
---|---|
bin | 1011111010110001011111… |
… | …0010011011000010101111 |
3 | 1201101202121021201220000212 |
4 | 2332230113302123002233 |
5 | 3204200144121022111 |
6 | 43512015213213035 |
7 | 2521520603546435 |
oct | 276542762330257 |
9 | 51352537656025 |
10 | 13104344314031 |
11 | 41a2580810273 |
12 | 157786249117b |
13 | 740971531679 |
14 | 33437a026d55 |
15 | 17ad19eaa98b |
hex | beb17c9b0af |
13104344314031 has 2 divisors, whose sum is σ = 13104344314032. Its totient is φ = 13104344314030.
The previous prime is 13104344313979. The next prime is 13104344314049. The reversal of 13104344314031 is 13041344340131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13104344314031 - 26 = 13104344313967 is a prime.
It is a super-2 number, since 2×131043443140312 (a number of 27 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13104644314031) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552172157015 + 6552172157016.
It is an arithmetic number, because the mean of its divisors is an integer number (6552172157016).
Almost surely, 213104344314031 is an apocalyptic number.
13104344314031 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104344314031 is an equidigital number, since it uses as much as digits as its factorization.
13104344314031 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 20736, while the sum is 32.
Adding to 13104344314031 its reverse (13041344340131), we get a palindrome (26145688654162).
The spelling of 13104344314031 in words is "thirteen trillion, one hundred four billion, three hundred forty-four million, three hundred fourteen thousand, thirty-one".
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