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13104403034124 = 2232822938684813
BaseRepresentation
bin1011111010110001101101…
…0010011011000000001100
31201101202202101020011212010
42332230123102123000030
53204200304134042444
643512025111541220
72521522215633153
oct276543322330014
951352671204763
1013104403034124
1141a2600977576
12157787a08a810
13740980750b9c
14334383b5059a
1517ad202092b9
hexbeb1b49b00c

13104403034124 has 24 divisors (see below), whose sum is σ = 30578024378160. Its totient is φ = 4367979492544.

The previous prime is 13104403034113. The next prime is 13104403034143. The reversal of 13104403034124 is 42143030440131.

It is a junction number, because it is equal to n+sod(n) for n = 13104403034091 and 13104403034100.

It is an unprimeable number.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 19003659 + ... + 19681154.

It is an arithmetic number, because the mean of its divisors is an integer number (1274084349090).

Almost surely, 213104403034124 is an apocalyptic number.

It is an amenable number.

13104403034124 is an abundant number, since it is smaller than the sum of its proper divisors (17473621344036).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104403034124 is a wasteful number, since it uses less digits than its factorization.

13104403034124 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 38713049 (or 38713047 counting only the distinct ones).

The product of its (nonzero) digits is 13824, while the sum is 30.

Adding to 13104403034124 its reverse (42143030440131), we get a palindrome (55247433474255).

The spelling of 13104403034124 in words is "thirteen trillion, one hundred four billion, four hundred three million, thirty-four thousand, one hundred twenty-four".

Divisors: 1 2 3 4 6 12 28229 56458 84687 112916 169374 338748 38684813 77369626 116054439 154739252 232108878 464217756 1092033586177 2184067172354 3276100758531 4368134344708 6552201517062 13104403034124