Base | Representation |
---|---|
bin | 1011111010110001101101… |
… | …0010011011000000001101 |
3 | 1201101202202101020011212011 |
4 | 2332230123102123000031 |
5 | 3204200304134043000 |
6 | 43512025111541221 |
7 | 2521522215633154 |
oct | 276543322330015 |
9 | 51352671204764 |
10 | 13104403034125 |
11 | 41a2600977577 |
12 | 157787a08a811 |
13 | 740980750ba0 |
14 | 334383b5059b |
15 | 17ad202092ba |
hex | beb1b49b00d |
13104403034125 has 32 divisors (see below), whose sum is σ = 17618196960000. Its totient is φ = 9673867252800.
The previous prime is 13104403034113. The next prime is 13104403034143. The reversal of 13104403034125 is 52143030440131.
13104403034125 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a de Polignac number, because none of the positive numbers 2k-13104403034125 is a prime.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 3528886 + ... + 6217864.
It is an arithmetic number, because the mean of its divisors is an integer number (550568655000).
Almost surely, 213104403034125 is an apocalyptic number.
It is an amenable number.
13104403034125 is a deficient number, since it is larger than the sum of its proper divisors (4513793925875).
13104403034125 is a wasteful number, since it uses less digits than its factorization.
13104403034125 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 2692006 (or 2691996 counting only the distinct ones).
The product of its (nonzero) digits is 17280, while the sum is 31.
Adding to 13104403034125 its reverse (52143030440131), we get a palindrome (65247433474256).
The spelling of 13104403034125 in words is "thirteen trillion, one hundred four billion, four hundred three million, thirty-four thousand, one hundred twenty-five".
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