Base | Representation |
---|---|
bin | 111101000001011010… |
… | …1010100001001101011 |
3 | 110112020200110121211120 |
4 | 1322002311110021223 |
5 | 4121334233030011 |
6 | 140111212230323 |
7 | 12316251621504 |
oct | 1720265241153 |
9 | 415220417746 |
10 | 131044033131 |
11 | 50636a38730 |
12 | 2149246b3a3 |
13 | c48528b20b |
14 | 64b1dd9bab |
15 | 361e841a06 |
hex | 1e82d5426b |
131044033131 has 32 divisors (see below), whose sum is σ = 194681802240. Its totient is φ = 77731180800.
The previous prime is 131044033121. The next prime is 131044033151. The reversal of 131044033131 is 131330440131.
It is not a de Polignac number, because 131044033131 - 26 = 131044033067 is a prime.
It is a super-2 number, since 2×1310440331312 (a number of 23 digits) contains 22 as substring.
It is not an unprimeable number, because it can be changed into a prime (131044033121) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 623746 + ... + 806936.
It is an arithmetic number, because the mean of its divisors is an integer number (6083806320).
Almost surely, 2131044033131 is an apocalyptic number.
131044033131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.
131044033131 is a deficient number, since it is larger than the sum of its proper divisors (63637769109).
131044033131 is a wasteful number, since it uses less digits than its factorization.
131044033131 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 183667.
The product of its (nonzero) digits is 1296, while the sum is 24.
Adding to 131044033131 its reverse (131330440131), we get a palindrome (262374473262).
The spelling of 131044033131 in words is "one hundred thirty-one billion, forty-four million, thirty-three thousand, one hundred thirty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.072 sec. • engine limits •