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13104405121050 = 23252239603720183
BaseRepresentation
bin1011111010110001101101…
…1010011000100000011010
31201101202202112011012120200
42332230123122120200122
53204200310202333200
643512025224403030
72521522242444405
oct276543332304032
951352675135520
1013104405121050
1141a2602072501
12157787a916476
13740981001a59
14334384134d3c
1517ad204bc800
hexbeb1b69881a

13104405121050 has 144 divisors (see below), whose sum is σ = 35362087038720. Its totient is φ = 3479137845120.

The previous prime is 13104405121001. The next prime is 13104405121051. The reversal of 13104405121050 is 5012150440131.

13104405121050 is a `hidden beast` number, since 1 + 3 + 1 + 0 + 4 + 40 + 512 + 105 + 0 = 666.

13104405121050 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is not an unprimeable number, because it can be changed into a prime (13104405121051) by changing a digit.

It is a polite number, since it can be written in 71 ways as a sum of consecutive naturals, for example, 649269259 + ... + 649289441.

It is an arithmetic number, because the mean of its divisors is an integer number (245570048880).

Almost surely, 213104405121050 is an apocalyptic number.

13104405121050 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is a practical number, because each smaller number is the sum of distinct divisors of 13104405121050, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (17681043519360).

13104405121050 is an abundant number, since it is smaller than the sum of its proper divisors (22257681917670).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13104405121050 is a wasteful number, since it uses less digits than its factorization.

13104405121050 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 26477 (or 26469 counting only the distinct ones).

The product of its (nonzero) digits is 2400, while the sum is 27.

Adding to 13104405121050 its reverse (5012150440131), we get a palindrome (18116555561181).

The spelling of 13104405121050 in words is "thirteen trillion, one hundred four billion, four hundred five million, one hundred twenty-one thousand, fifty".

Divisors: 1 2 3 5 6 9 10 15 18 25 30 45 50 75 90 150 225 239 450 478 717 1195 1434 2151 2390 3585 4302 5975 6037 7170 10755 11950 12074 17925 18111 20183 21510 30185 35850 36222 40366 53775 54333 60370 60549 90555 100915 107550 108666 121098 150925 181110 181647 201830 271665 301850 302745 363294 452775 504575 543330 605490 905550 908235 1009150 1358325 1442843 1513725 1816470 2716650 2885686 3027450 4328529 4541175 4823737 7214215 8657058 9082350 9647474 12985587 14428430 14471211 21642645 24118685 25971174 28942422 36071075 43285290 43413633 48237370 64927935 72142150 72356055 86827266 108213225 120593425 121844771 129855870 144712110 216426450 217068165 241186850 243689542 324639675 361780275 365534313 434136330 609223855 649279350 723560550 731068626 1085340825 1096602939 1218447710 1827671565 2170681650 2193205878 3046119275 3655343130 5483014695 6092238550 9138357825 10966029390 18276715650 27415073475 29120900269 54830146950 58241800538 87362700807 145604501345 174725401614 262088102421 291209002690 436813504035 524176204842 728022506725 873627008070 1310440512105 1456045013450 2184067520175 2620881024210 4368135040350 6552202560525 13104405121050