Base | Representation |
---|---|
bin | 1011111010110001110001… |
… | …1100011101110000110011 |
3 | 1201101202210201202022022111 |
4 | 2332230130130131300303 |
5 | 3204200324121202313 |
6 | 43512031043550151 |
7 | 2521522542624025 |
oct | 276543434356063 |
9 | 51352721668274 |
10 | 13104422444083 |
11 | 41a2610924563 |
12 | 157788468b357 |
13 | 740984788879 |
14 | 334386564015 |
15 | 17ad21c9043d |
hex | beb1c71dc33 |
13104422444083 has 2 divisors, whose sum is σ = 13104422444084. Its totient is φ = 13104422444082.
The previous prime is 13104422444059. The next prime is 13104422444101. The reversal of 13104422444083 is 38044422440131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13104422444083 - 217 = 13104422313011 is a prime.
It is not a weakly prime, because it can be changed into another prime (13104422444483) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552211222041 + 6552211222042.
It is an arithmetic number, because the mean of its divisors is an integer number (6552211222042).
Almost surely, 213104422444083 is an apocalyptic number.
13104422444083 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104422444083 is an equidigital number, since it uses as much as digits as its factorization.
13104422444083 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 294912, while the sum is 40.
The spelling of 13104422444083 in words is "thirteen trillion, one hundred four billion, four hundred twenty-two million, four hundred forty-four thousand, eighty-three".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •