Base | Representation |
---|---|
bin | 1011111010110001110001… |
… | …1100011101110111000011 |
3 | 1201101202210201202022212022 |
4 | 2332230130130131313003 |
5 | 3204200324121210413 |
6 | 43512031043552055 |
7 | 2521522542625136 |
oct | 276543434356703 |
9 | 51352721668768 |
10 | 13104422444483 |
11 | 41a2610924897 |
12 | 157788468b62b |
13 | 740984788ac6 |
14 | 33438656421d |
15 | 17ad21c90608 |
hex | beb1c71ddc3 |
13104422444483 has 2 divisors, whose sum is σ = 13104422444484. Its totient is φ = 13104422444482.
The previous prime is 13104422444467. The next prime is 13104422444537. The reversal of 13104422444483 is 38444422440131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 13104422444483 - 24 = 13104422444467 is a prime.
It is not a weakly prime, because it can be changed into another prime (13104422444083) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552211222241 + 6552211222242.
It is an arithmetic number, because the mean of its divisors is an integer number (6552211222242).
Almost surely, 213104422444483 is an apocalyptic number.
13104422444483 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104422444483 is an equidigital number, since it uses as much as digits as its factorization.
13104422444483 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1179648, while the sum is 44.
The spelling of 13104422444483 in words is "thirteen trillion, one hundred four billion, four hundred twenty-two million, four hundred forty-four thousand, four hundred eighty-three".
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