Base | Representation |
---|---|
bin | 1011111010110001110001… |
… | …1100011101110001000101 |
3 | 1201101202210201202022100011 |
4 | 2332230130130131301011 |
5 | 3204200324121202401 |
6 | 43512031043550221 |
7 | 2521522542624052 |
oct | 276543434356105 |
9 | 51352721668304 |
10 | 13104422444101 |
11 | 41a261092457a |
12 | 157788468b371 |
13 | 740984788891 |
14 | 334386564029 |
15 | 17ad21c90451 |
hex | beb1c71dc45 |
13104422444101 has 2 divisors, whose sum is σ = 13104422444102. Its totient is φ = 13104422444100.
The previous prime is 13104422444083. The next prime is 13104422444123. The reversal of 13104422444101 is 10144422440131.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 9508188096225 + 3596234347876 = 3083535^2 + 1896374^2 .
It is a cyclic number.
It is not a de Polignac number, because 13104422444101 - 211 = 13104422442053 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (13104422444131) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552211222050 + 6552211222051.
It is an arithmetic number, because the mean of its divisors is an integer number (6552211222051).
Almost surely, 213104422444101 is an apocalyptic number.
It is an amenable number.
13104422444101 is a deficient number, since it is larger than the sum of its proper divisors (1).
13104422444101 is an equidigital number, since it uses as much as digits as its factorization.
13104422444101 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12288, while the sum is 31.
Adding to 13104422444101 its reverse (10144422440131), we get a palindrome (23248844884232).
The spelling of 13104422444101 in words is "thirteen trillion, one hundred four billion, four hundred twenty-two million, four hundred forty-four thousand, one hundred one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.068 sec. • engine limits •