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13104422444103 = 39745032379533
BaseRepresentation
bin1011111010110001110001…
…1100011101110001000111
31201101202210201202022100020
42332230130130131301013
53204200324121202403
643512031043550223
72521522542624054
oct276543434356107
951352721668306
1013104422444103
1141a2610924581
12157788468b373
13740984788893
1433438656402b
1517ad21c90453
hexbeb1c71dc47

13104422444103 has 8 divisors (see below), whose sum is σ = 17652692777328. Its totient is φ = 8646216870144.

The previous prime is 13104422444101. The next prime is 13104422444123. The reversal of 13104422444103 is 30144422440131.

It is a happy number.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 13104422444103 - 21 = 13104422444101 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13104422444101) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 22516189476 + ... + 22516190057.

It is an arithmetic number, because the mean of its divisors is an integer number (2206586597166).

Almost surely, 213104422444103 is an apocalyptic number.

13104422444103 is a deficient number, since it is larger than the sum of its proper divisors (4548270333225).

13104422444103 is an equidigital number, since it uses as much as digits as its factorization.

13104422444103 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 45032379633.

The product of its (nonzero) digits is 36864, while the sum is 33.

Adding to 13104422444103 its reverse (30144422440131), we get a palindrome (43248844884234).

The spelling of 13104422444103 in words is "thirteen trillion, one hundred four billion, four hundred twenty-two million, four hundred forty-four thousand, one hundred three".

Divisors: 1 3 97 291 45032379533 135097138599 4368140814701 13104422444103