Base | Representation |
---|---|
bin | 111101000001011011… |
… | …0110110000110100111 |
3 | 110112020201020000012021 |
4 | 1322002312312012213 |
5 | 4121334333344333 |
6 | 140111225004011 |
7 | 12316255212304 |
oct | 1720266660647 |
9 | 415221200167 |
10 | 131044434343 |
11 | 50637192109 |
12 | 21492623607 |
13 | c48539ba14 |
14 | 64b20a20ab |
15 | 361e8c082d |
hex | 1e82db61a7 |
131044434343 has 4 divisors (see below), whose sum is σ = 131048961928. Its totient is φ = 131039906760.
The previous prime is 131044434319. The next prime is 131044434361. The reversal of 131044434343 is 343434440131.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131044434343 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 131044434299 and 131044434308.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131045434343) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2220096 + ... + 2278357.
It is an arithmetic number, because the mean of its divisors is an integer number (32762240482).
Almost surely, 2131044434343 is an apocalyptic number.
131044434343 is a deficient number, since it is larger than the sum of its proper divisors (4527585).
131044434343 is an equidigital number, since it uses as much as digits as its factorization.
131044434343 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4527584.
The product of its (nonzero) digits is 82944, while the sum is 34.
Adding to 131044434343 its reverse (343434440131), we get a palindrome (474478874474).
The spelling of 131044434343 in words is "one hundred thirty-one billion, forty-four million, four hundred thirty-four thousand, three hundred forty-three".
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