Base | Representation |
---|---|
bin | 111101000001011011… |
… | …0110110000110111001 |
3 | 110112020201020000012221 |
4 | 1322002312312012321 |
5 | 4121334333344421 |
6 | 140111225004041 |
7 | 12316255212331 |
oct | 1720266660671 |
9 | 415221200187 |
10 | 131044434361 |
11 | 50637192125 |
12 | 21492623621 |
13 | c48539ba29 |
14 | 64b20a20c1 |
15 | 361e8c0841 |
hex | 1e82db61b9 |
131044434361 has 2 divisors, whose sum is σ = 131044434362. Its totient is φ = 131044434360.
The previous prime is 131044434319. The next prime is 131044434377. The reversal of 131044434361 is 163434440131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 91775067136 + 39269367225 = 302944^2 + 198165^2 .
It is a cyclic number.
It is not a de Polignac number, because 131044434361 - 217 = 131044303289 is a prime.
It is not a weakly prime, because it can be changed into another prime (131044434061) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522217180 + 65522217181.
It is an arithmetic number, because the mean of its divisors is an integer number (65522217181).
Almost surely, 2131044434361 is an apocalyptic number.
It is an amenable number.
131044434361 is a deficient number, since it is larger than the sum of its proper divisors (1).
131044434361 is an equidigital number, since it uses as much as digits as its factorization.
131044434361 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 41472, while the sum is 34.
Adding to 131044434361 its reverse (163434440131), we get a palindrome (294478874492).
The spelling of 131044434361 in words is "one hundred thirty-one billion, forty-four million, four hundred thirty-four thousand, three hundred sixty-one".
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