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131044441304551 is a prime number
BaseRepresentation
bin11101110010111100101001…
…010111111010110111100111
3122011222201121102120220020111
4131302330221113322313213
5114134013003433221201
61142412552451513451
736413435263260205
oct3562745127726747
9564881542526214
10131044441304551
11388336a9881a95
121284535a2b8887
13581758ca98828
1424508289a0075
151023b7768db51
hex772f295fade7

131044441304551 has 2 divisors, whose sum is σ = 131044441304552. Its totient is φ = 131044441304550.

The previous prime is 131044441304503. The next prime is 131044441304599. The reversal of 131044441304551 is 155403144440131.

It is a balanced prime because it is at equal distance from previous prime (131044441304503) and next prime (131044441304599).

It is a cyclic number.

It is not a de Polignac number, because 131044441304551 - 241 = 128845418048999 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131044441304251) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522220652275 + 65522220652276.

It is an arithmetic number, because the mean of its divisors is an integer number (65522220652276).

Almost surely, 2131044441304551 is an apocalyptic number.

131044441304551 is a deficient number, since it is larger than the sum of its proper divisors (1).

131044441304551 is an equidigital number, since it uses as much as digits as its factorization.

131044441304551 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 230400, while the sum is 40.

Adding to 131044441304551 its reverse (155403144440131), we get a palindrome (286447585744682).

The spelling of 131044441304551 in words is "one hundred thirty-one trillion, forty-four billion, four hundred forty-one million, three hundred four thousand, five hundred fifty-one".