13104444335501 has 2 divisors, whose sum is σ = 13104444335502. Its totient is φ = 13104444335500.

The previous prime is 13104444335483. The next prime is 13104444335551. The reversal of 13104444335501 is 10553344440131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9560148618601 + 3544295716900 = 3091949^2 + 1882630^2 .

It is a cyclic number.

It is not a de Polignac number, because 13104444335501 - 2¹⁰ = 13104444334477 is a prime.

It is a super-2 number, since 2×13104444335501² (a number of 27 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104444335551) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552222167750 + 6552222167751.

It is an arithmetic number, because the mean of its divisors is an integer number (6552222167751).

Almost surely, 2^{13104444335501} is an apocalyptic number.

It is an amenable number.

13104444335501 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104444335501 is an equidigital number, since it uses as much as digits as its factorization.

13104444335501 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 172800, while the sum is 38.

Adding to 13104444335501 its reverse (10553344440131), we get a palindrome (23657788775632).

The spelling of 13104444335501 in words is "thirteen trillion, one hundred four billion, four hundred forty-four million, three hundred thirty-five thousand, five hundred one".