Base | Representation |
---|---|
bin | 11101110010111101011001… |
… | …110010001111100000110111 |
3 | 122011222210201000220021100002 |
4 | 131302331121302033200313 |
5 | 114134021134344324343 |
6 | 1142413205224141515 |
7 | 36413464355023532 |
oct | 3562753162174067 |
9 | 564883630807302 |
10 | 131045253511223 |
11 | 38833a8629a977 |
12 | 1284554630789b |
13 | 581768c1337ac |
14 | 24508a47c5a19 |
15 | 1023bc3b278b8 |
hex | 772f59c8f837 |
131045253511223 has 2 divisors, whose sum is σ = 131045253511224. Its totient is φ = 131045253511222.
The previous prime is 131045253511219. The next prime is 131045253511301. The reversal of 131045253511223 is 322115352540131.
It is a weak prime.
It is an emirp because it is prime and its reverse (322115352540131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 131045253511223 - 22 = 131045253511219 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131045253519223) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522626755611 + 65522626755612.
It is an arithmetic number, because the mean of its divisors is an integer number (65522626755612).
Almost surely, 2131045253511223 is an apocalyptic number.
131045253511223 is a deficient number, since it is larger than the sum of its proper divisors (1).
131045253511223 is an equidigital number, since it uses as much as digits as its factorization.
131045253511223 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 108000, while the sum is 38.
The spelling of 131045253511223 in words is "one hundred thirty-one trillion, forty-five billion, two hundred fifty-three million, five hundred eleven thousand, two hundred twenty-three".
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