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131045253511223 is a prime number
BaseRepresentation
bin11101110010111101011001…
…110010001111100000110111
3122011222210201000220021100002
4131302331121302033200313
5114134021134344324343
61142413205224141515
736413464355023532
oct3562753162174067
9564883630807302
10131045253511223
1138833a8629a977
121284554630789b
13581768c1337ac
1424508a47c5a19
151023bc3b278b8
hex772f59c8f837

131045253511223 has 2 divisors, whose sum is σ = 131045253511224. Its totient is φ = 131045253511222.

The previous prime is 131045253511219. The next prime is 131045253511301. The reversal of 131045253511223 is 322115352540131.

It is a weak prime.

It is an emirp because it is prime and its reverse (322115352540131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 131045253511223 - 22 = 131045253511219 is a prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131045253519223) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522626755611 + 65522626755612.

It is an arithmetic number, because the mean of its divisors is an integer number (65522626755612).

Almost surely, 2131045253511223 is an apocalyptic number.

131045253511223 is a deficient number, since it is larger than the sum of its proper divisors (1).

131045253511223 is an equidigital number, since it uses as much as digits as its factorization.

131045253511223 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 108000, while the sum is 38.

The spelling of 131045253511223 in words is "one hundred thirty-one trillion, forty-five billion, two hundred fifty-three million, five hundred eleven thousand, two hundred twenty-three".