Base | Representation |
---|---|
bin | 11101110010111101100010… |
… | …100010000000011100011011 |
3 | 122011222211002021000101021202 |
4 | 131302331202202000130123 |
5 | 114134021434431001024 |
6 | 1142413231545224415 |
7 | 36413501116212014 |
oct | 3562754242003433 |
9 | 564884067011252 |
10 | 131045400250139 |
11 | 38834051105001 |
12 | 1284558749210b |
13 | 58176b366025b |
14 | 24508ba0a200b |
15 | 1023bd1960bae |
hex | 772f6288071b |
131045400250139 has 2 divisors, whose sum is σ = 131045400250140. Its totient is φ = 131045400250138.
The previous prime is 131045400250109. The next prime is 131045400250201. The reversal of 131045400250139 is 931052004540131.
It is a happy number.
It is a weak prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131045400250139 is a prime.
It is not a weakly prime, because it can be changed into another prime (131045400250109) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (23) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65522700125069 + 65522700125070.
It is an arithmetic number, because the mean of its divisors is an integer number (65522700125070).
Almost surely, 2131045400250139 is an apocalyptic number.
131045400250139 is a deficient number, since it is larger than the sum of its proper divisors (1).
131045400250139 is an equidigital number, since it uses as much as digits as its factorization.
131045400250139 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 64800, while the sum is 38.
The spelling of 131045400250139 in words is "one hundred thirty-one trillion, forty-five billion, four hundred million, two hundred fifty thousand, one hundred thirty-nine".
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