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13104831351127 is a prime number
BaseRepresentation
bin1011111010110011010011…
…0100010100100101010111
31201101210212020011221022211
42332230310310110211113
53204202143311214002
643512135412134251
72521535636363605
oct276546464244527
951353766157284
1013104831351127
1141a280072346a
121577979607387
13740a1b3c83b9
143343c49a6875
1517ad47b12dd7
hexbeb34d14957

13104831351127 has 2 divisors, whose sum is σ = 13104831351128. Its totient is φ = 13104831351126.

The previous prime is 13104831351097. The next prime is 13104831351203. The reversal of 13104831351127 is 72115313840131.

It is a happy number.

It is a weak prime.

It is an emirp because it is prime and its reverse (72115313840131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13104831351127 - 223 = 13104822962519 is a prime.

It is a super-2 number, since 2×131048313511272 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13104831351127.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13104831351827) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552415675563 + 6552415675564.

It is an arithmetic number, because the mean of its divisors is an integer number (6552415675564).

Almost surely, 213104831351127 is an apocalyptic number.

13104831351127 is a deficient number, since it is larger than the sum of its proper divisors (1).

13104831351127 is an equidigital number, since it uses as much as digits as its factorization.

13104831351127 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 60480, while the sum is 40.

The spelling of 13104831351127 in words is "thirteen trillion, one hundred four billion, eight hundred thirty-one million, three hundred fifty-one thousand, one hundred twenty-seven".