Base | Representation |
---|---|
bin | 1011111010110011111101… |
… | …1110000000101111001011 |
3 | 1201101211022200102212220021 |
4 | 2332230333132000233023 |
5 | 3204203030033131133 |
6 | 43512205234241311 |
7 | 2521543236331540 |
oct | 276547736005713 |
9 | 51354280385807 |
10 | 13105010052043 |
11 | 41a2892589078 |
12 | 1577a09426237 |
13 | 740a49435ba0 |
14 | 334400602bc7 |
15 | 17ad5866152d |
hex | beb3f780bcb |
13105010052043 has 32 divisors (see below), whose sum is σ = 16927801261056. Its totient is φ = 9860652160128.
The previous prime is 13105010052041. The next prime is 13105010052067. The reversal of 13105010052043 is 34025001050131.
It is a happy number.
It is not a de Polignac number, because 13105010052043 - 21 = 13105010052041 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 13105010051999 and 13105010052017.
It is not an unprimeable number, because it can be changed into a prime (13105010052041) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 17734305 + ... + 18458482.
It is an arithmetic number, because the mean of its divisors is an integer number (528993789408).
Almost surely, 213105010052043 is an apocalyptic number.
13105010052043 is a gapful number since it is divisible by the number (13) formed by its first and last digit.
13105010052043 is a deficient number, since it is larger than the sum of its proper divisors (3822791209013).
13105010052043 is a wasteful number, since it uses less digits than its factorization.
13105010052043 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 36193003.
The product of its (nonzero) digits is 1800, while the sum is 25.
The spelling of 13105010052043 in words is "thirteen trillion, one hundred five billion, ten million, fifty-two thousand, forty-three".
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