Base | Representation |
---|---|
bin | 111101000001100111… |
… | …0000111010110011100 |
3 | 110112021010200220202121 |
4 | 1322003032013112130 |
5 | 4121342414044200 |
6 | 140112003432324 |
7 | 12316361106400 |
oct | 1720316072634 |
9 | 415233626677 |
10 | 131050534300 |
11 | 5063a6790a4 |
12 | 214946856a4 |
13 | c48672636a |
14 | 64b2c0d100 |
15 | 36201c7e1a |
hex | 1e8338759c |
131050534300 has 108 divisors (see below), whose sum is σ = 334795681080. Its totient is φ = 44390129280.
The previous prime is 131050534297. The next prime is 131050534301. The reversal of 131050534300 is 3435050131.
131050534300 is digitally balanced in base 3, because in such base it contains all the possibile digits an equal number of times.
It is a Harshad number since it is a multiple of its sum of digits (25).
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131050534301) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 35 ways as a sum of consecutive naturals, for example, 245586 + ... + 567814.
It is an arithmetic number, because the mean of its divisors is an integer number (3099960010).
Almost surely, 2131050534300 is an apocalyptic number.
131050534300 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
It is a practical number, because each smaller number is the sum of distinct divisors of 131050534300, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (167397840540).
131050534300 is an abundant number, since it is smaller than the sum of its proper divisors (203745146780).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131050534300 is a wasteful number, since it uses less digits than its factorization.
131050534300 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 322340 (or 322326 counting only the distinct ones).
The product of its (nonzero) digits is 2700, while the sum is 25.
Adding to 131050534300 its reverse (3435050131), we get a palindrome (134485584431).
The spelling of 131050534300 in words is "one hundred thirty-one billion, fifty million, five hundred thirty-four thousand, three hundred".
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