13105412025133 has 2 divisors, whose sum is σ = 13105412025134. Its totient is φ = 13105412025132.

The previous prime is 13105412025131. The next prime is 13105412025149. The reversal of 13105412025133 is 33152021450131.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 10309249483204 + 2796162541929 = 3210802^2 + 1672173^2 .

It is an emirp because it is prime and its reverse (33152021450131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13105412025133 - 2¹ = 13105412025131 is a prime.

Together with 13105412025131, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 13105412025095 and 13105412025104.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13105412025131) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552706012566 + 6552706012567.

It is an arithmetic number, because the mean of its divisors is an integer number (6552706012567).

Almost surely, 2^{13105412025133} is an apocalyptic number.

It is an amenable number.

13105412025133 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105412025133 is an equidigital number, since it uses as much as digits as its factorization.

13105412025133 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 10800, while the sum is 31.

Adding to 13105412025133 its reverse (33152021450131), we get a palindrome (46257433475264).

The spelling of 13105412025133 in words is "thirteen trillion, one hundred five billion, four hundred twelve million, twenty-five thousand, one hundred thirty-three".