Base | Representation |
---|---|
bin | 111101000001101110… |
… | …0000010101010111111 |
3 | 110112021101120101210022 |
4 | 1322003130002222333 |
5 | 4121344332411101 |
6 | 140112214002355 |
7 | 12316434123311 |
oct | 1720334025277 |
9 | 415241511708 |
10 | 131054185151 |
11 | 5064174202a |
12 | 214959463bb |
13 | c487404026 |
14 | 64b34bd7b1 |
15 | 3620699a1b |
hex | 1e83702abf |
131054185151 has 2 divisors, whose sum is σ = 131054185152. Its totient is φ = 131054185150.
The previous prime is 131054185133. The next prime is 131054185153. The reversal of 131054185151 is 151581450131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131054185151 - 210 = 131054184127 is a prime.
Together with 131054185153, it forms a pair of twin primes.
It is a Chen prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131054185153) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65527092575 + 65527092576.
It is an arithmetic number, because the mean of its divisors is an integer number (65527092576).
Almost surely, 2131054185151 is an apocalyptic number.
131054185151 is a deficient number, since it is larger than the sum of its proper divisors (1).
131054185151 is an equidigital number, since it uses as much as digits as its factorization.
131054185151 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 12000, while the sum is 35.
The spelling of 131054185151 in words is "one hundred thirty-one billion, fifty-four million, one hundred eighty-five thousand, one hundred fifty-one".
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