Base | Representation |
---|---|
bin | 1011111010110101100011… |
… | …0011001001001110001011 |
3 | 1201101212102022002121101102 |
4 | 2332231120303021032023 |
5 | 3204204412331202334 |
6 | 43512315335012015 |
7 | 2521556616452621 |
oct | 276553063111613 |
9 | 51355368077342 |
10 | 13105435022219 |
11 | 41a2a904594a1 |
12 | 1577b0780a00b |
13 | 740ab64aac27 |
14 | 334440c27511 |
15 | 17ad80b0867e |
hex | beb58cc938b |
13105435022219 has 2 divisors, whose sum is σ = 13105435022220. Its totient is φ = 13105435022218.
The previous prime is 13105435022203. The next prime is 13105435022221. The reversal of 13105435022219 is 91222053450131.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 13105435022219 - 24 = 13105435022203 is a prime.
It is a super-2 number, since 2×131054350222192 (a number of 27 digits) contains 22 as substring.
Together with 13105435022221, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (13105435025219) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552717511109 + 6552717511110.
It is an arithmetic number, because the mean of its divisors is an integer number (6552717511110).
Almost surely, 213105435022219 is an apocalyptic number.
13105435022219 is a deficient number, since it is larger than the sum of its proper divisors (1).
13105435022219 is an equidigital number, since it uses as much as digits as its factorization.
13105435022219 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 64800, while the sum is 38.
The spelling of 13105435022219 in words is "thirteen trillion, one hundred five billion, four hundred thirty-five million, twenty-two thousand, two hundred nineteen".
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