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13105435022219 is a prime number
BaseRepresentation
bin1011111010110101100011…
…0011001001001110001011
31201101212102022002121101102
42332231120303021032023
53204204412331202334
643512315335012015
72521556616452621
oct276553063111613
951355368077342
1013105435022219
1141a2a904594a1
121577b0780a00b
13740ab64aac27
14334440c27511
1517ad80b0867e
hexbeb58cc938b

13105435022219 has 2 divisors, whose sum is σ = 13105435022220. Its totient is φ = 13105435022218.

The previous prime is 13105435022203. The next prime is 13105435022221. The reversal of 13105435022219 is 91222053450131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13105435022219 - 24 = 13105435022203 is a prime.

It is a super-2 number, since 2×131054350222192 (a number of 27 digits) contains 22 as substring.

Together with 13105435022221, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (13105435025219) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552717511109 + 6552717511110.

It is an arithmetic number, because the mean of its divisors is an integer number (6552717511110).

Almost surely, 213105435022219 is an apocalyptic number.

13105435022219 is a deficient number, since it is larger than the sum of its proper divisors (1).

13105435022219 is an equidigital number, since it uses as much as digits as its factorization.

13105435022219 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 64800, while the sum is 38.

The spelling of 13105435022219 in words is "thirteen trillion, one hundred five billion, four hundred thirty-five million, twenty-two thousand, two hundred nineteen".