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13105441121232 = 243273030023359
BaseRepresentation
bin1011111010110101100100…
…1010011010001111010000
31201101212102201120110122210
42332231121022122033100
53204204420411334412
643512320113432120
72521560022344165
oct276553112321720
951355381513583
1013105441121232
1141a2a939447a9
121577b0986b640
13740ab7835005
1433444197406c
1517ad8141083c
hexbeb5929a3d0

13105441121232 has 20 divisors (see below), whose sum is σ = 33855722896640. Its totient is φ = 4368480373728.

The previous prime is 13105441121207. The next prime is 13105441121237. The reversal of 13105441121232 is 23212114450131.

It is a super-2 number, since 2×131054411212322 (a number of 27 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 13105441121232.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (13105441121237) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 136515011632 + ... + 136515011727.

It is an arithmetic number, because the mean of its divisors is an integer number (1692786144832).

Almost surely, 213105441121232 is an apocalyptic number.

13105441121232 is a gapful number since it is divisible by the number (12) formed by its first and last digit.

It is an amenable number.

13105441121232 is an abundant number, since it is smaller than the sum of its proper divisors (20750281775408).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13105441121232 is a wasteful number, since it uses less digits than its factorization.

13105441121232 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 273030023370 (or 273030023364 counting only the distinct ones).

The product of its (nonzero) digits is 5760, while the sum is 30.

Adding to 13105441121232 its reverse (23212114450131), we get a palindrome (36317555571363).

The spelling of 13105441121232 in words is "thirteen trillion, one hundred five billion, four hundred forty-one million, one hundred twenty-one thousand, two hundred thirty-two".

Divisors: 1 2 3 4 6 8 12 16 24 48 273030023359 546060046718 819090070077 1092120093436 1638180140154 2184240186872 3276360280308 4368480373744 6552720560616 13105441121232