Base | Representation |
---|---|
bin | 11000011010010011… |
… | …00110101011001001 |
3 | 1020211100100120100121 |
4 | 30031021212223021 |
5 | 203320003222101 |
6 | 10004240503241 |
7 | 642524053015 |
oct | 141511465311 |
9 | 36740316317 |
10 | 13105523401 |
11 | 56157a9783 |
12 | 265901ab21 |
13 | 130b1ca599 |
14 | 8c4797545 |
15 | 51a8480a1 |
hex | 30d266ac9 |
13105523401 has 2 divisors, whose sum is σ = 13105523402. Its totient is φ = 13105523400.
The previous prime is 13105523377. The next prime is 13105523419. The reversal of 13105523401 is 10432550131.
It is a happy number.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 9482085376 + 3623438025 = 97376^2 + 60195^2 .
It is an emirp because it is prime and its reverse (10432550131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13105523401 - 211 = 13105521353 is a prime.
It is a super-2 number, since 2×131055234012 (a number of 21 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (13105523461) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6552761700 + 6552761701.
It is an arithmetic number, because the mean of its divisors is an integer number (6552761701).
Almost surely, 213105523401 is an apocalyptic number.
It is an amenable number.
13105523401 is a deficient number, since it is larger than the sum of its proper divisors (1).
13105523401 is an equidigital number, since it uses as much as digits as its factorization.
13105523401 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1800, while the sum is 25.
The spelling of 13105523401 in words is "thirteen billion, one hundred five million, five hundred twenty-three thousand, four hundred one".
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