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131055541200444 = 22377125438641147
BaseRepresentation
bin11101110011000110111110…
…111110101010011000111100
3122012000210021000000000212210
4131303012332332222120330
5114134203222021403234
61142422030125100420
736414310324652550
oct3563067676523074
9565023230000783
10131055541200444
1138838385440073
12128475376b7710
13581863b5cb473
14245119cc35860
1510240c6db1be9
hex7731befaa63c

131055541200444 has 96 divisors (see below), whose sum is σ = 354543122497536. Its totient is φ = 36902532461760.

The previous prime is 131055541200431. The next prime is 131055541200457. The reversal of 131055541200444 is 444002145550131.

It is an interprime number because it is at equal distance from previous prime (131055541200431) and next prime (131055541200457).

It is a congruent number.

It is an unprimeable number.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 10845879 + ... + 19487025.

It is an arithmetic number, because the mean of its divisors is an integer number (3693157526016).

Almost surely, 2131055541200444 is an apocalyptic number.

131055541200444 is a gapful number since it is divisible by the number (14) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 131055541200444, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (177271561248768).

131055541200444 is an abundant number, since it is smaller than the sum of its proper divisors (223487581297092).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

131055541200444 is a wasteful number, since it uses less digits than its factorization.

131055541200444 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 8643775 (or 8643773 counting only the distinct ones).

The product of its (nonzero) digits is 192000, while the sum is 39.

Adding to 131055541200444 its reverse (444002145550131), we get a palindrome (575057686750575).

The spelling of 131055541200444 in words is "one hundred thirty-one trillion, fifty-five billion, five hundred forty-one million, two hundred thousand, four hundred forty-four".

Divisors: 1 2 3 4 6 7 12 14 21 28 42 71 84 142 213 284 426 497 852 994 1491 1988 2543 2982 5086 5964 7629 10172 15258 17801 30516 35602 53403 71204 106806 180553 213612 361106 541659 722212 1083318 1263871 2166636 2527742 3791613 5055484 7583226 8641147 15166452 17282294 25923441 34564588 51846882 60488029 103693764 120976058 181464087 241952116 362928174 613521437 725856348 1227042874 1840564311 2454085748 3681128622 4294650059 7362257244 8589300118 12883950177 17178600236 21974436821 25767900354 43948873642 51535800708 65923310463 87897747284 131846620926 153821057747 263693241852 307642115494 461463173241 615284230988 922926346482 1560185014291 1845852692964 3120370028582 4680555042873 6240740057164 9361110085746 10921295100037 18722220171492 21842590200074 32763885300111 43685180400148 65527770600222 131055541200444