Base | Representation |
---|---|
bin | 111101000001110010… |
… | …0101011101011100101 |
3 | 110112021112211110221212 |
4 | 1322003210223223211 |
5 | 4121400422402102 |
6 | 140112334321205 |
7 | 12316462306214 |
oct | 1720344535345 |
9 | 415245743855 |
10 | 131056450277 |
11 | 50642a49935 |
12 | 21496659205 |
13 | c487a1803c |
14 | 64b390d07b |
15 | 3620995c52 |
hex | 1e8392bae5 |
131056450277 has 2 divisors, whose sum is σ = 131056450278. Its totient is φ = 131056450276.
The previous prime is 131056450241. The next prime is 131056450313. The reversal of 131056450277 is 772054650131.
It is a balanced prime because it is at equal distance from previous prime (131056450241) and next prime (131056450313).
It can be written as a sum of positive squares in only one way, i.e., 66085499041 + 64970951236 = 257071^2 + 254894^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-131056450277 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131056453277) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65528225138 + 65528225139.
It is an arithmetic number, because the mean of its divisors is an integer number (65528225139).
Almost surely, 2131056450277 is an apocalyptic number.
It is an amenable number.
131056450277 is a deficient number, since it is larger than the sum of its proper divisors (1).
131056450277 is an equidigital number, since it uses as much as digits as its factorization.
131056450277 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 176400, while the sum is 41.
The spelling of 131056450277 in words is "one hundred thirty-one billion, fifty-six million, four hundred fifty thousand, two hundred seventy-seven".
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