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131058131305679 is a prime number
BaseRepresentation
bin11101110011001001011001…
…010111001000010011001111
3122012001000221111202000022022
4131303021121113020103033
5114134224023103240204
61142423135132040355
736414431445333014
oct3563113127102317
9565030844660268
10131058131305679
1138839494497506
1212847b3b0030bb
1358189620b8706
142451366c1d70b
1510241c948a5be
hex7732595c84cf

131058131305679 has 2 divisors, whose sum is σ = 131058131305680. Its totient is φ = 131058131305678.

The previous prime is 131058131305669. The next prime is 131058131305723. The reversal of 131058131305679 is 976503131850131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131058131305679 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 131058131305679.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131058131305669) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65529065652839 + 65529065652840.

It is an arithmetic number, because the mean of its divisors is an integer number (65529065652840).

Almost surely, 2131058131305679 is an apocalyptic number.

131058131305679 is a deficient number, since it is larger than the sum of its proper divisors (1).

131058131305679 is an equidigital number, since it uses as much as digits as its factorization.

131058131305679 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 2041200, while the sum is 53.

The spelling of 131058131305679 in words is "one hundred thirty-one trillion, fifty-eight billion, one hundred thirty-one million, three hundred five thousand, six hundred seventy-nine".