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13106244887 is a prime number
BaseRepresentation
bin11000011010011000…
…10110110100010111
31020211101201020001022
430031030112310113
5203320144314022
610004304151355
7642533146331
oct141514266427
936741636038
1013106244887
11561615184a
12265930855b
13130b3c0ab8
148c4904451
1551a93bc42
hex30d316d17

13106244887 has 2 divisors, whose sum is σ = 13106244888. Its totient is φ = 13106244886.

The previous prime is 13106244863. The next prime is 13106244889. The reversal of 13106244887 is 78844260131.

13106244887 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13106244887 - 214 = 13106228503 is a prime.

Together with 13106244889, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13106244889) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6553122443 + 6553122444.

It is an arithmetic number, because the mean of its divisors is an integer number (6553122444).

Almost surely, 213106244887 is an apocalyptic number.

13106244887 is a deficient number, since it is larger than the sum of its proper divisors (1).

13106244887 is an equidigital number, since it uses as much as digits as its factorization.

13106244887 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 258048, while the sum is 44.

The spelling of 13106244887 in words is "thirteen billion, one hundred six million, two hundred forty-four thousand, eight hundred eighty-seven".