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13106883479 is a prime number
BaseRepresentation
bin11000011010011101…
…10010101110010111
31020211102220200000212
430031032302232113
5203320330232404
610004330000035
7642541446164
oct141516625627
936742820025
1013106883479
115616548608
12265957601b
13130b585671
148c4a2d06b
1551aa1606e
hex30d3b2b97

13106883479 has 2 divisors, whose sum is σ = 13106883480. Its totient is φ = 13106883478.

The previous prime is 13106883473. The next prime is 13106883481. The reversal of 13106883479 is 97438860131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13106883479 - 24 = 13106883463 is a prime.

It is a super-3 number, since 3×131068834793 (a number of 31 digits) contains 333 as substring.

Together with 13106883481, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13106883473) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6553441739 + 6553441740.

It is an arithmetic number, because the mean of its divisors is an integer number (6553441740).

Almost surely, 213106883479 is an apocalyptic number.

13106883479 is a deficient number, since it is larger than the sum of its proper divisors (1).

13106883479 is an equidigital number, since it uses as much as digits as its factorization.

13106883479 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 870912, while the sum is 50.

The spelling of 13106883479 in words is "thirteen billion, one hundred six million, eight hundred eighty-three thousand, four hundred seventy-nine".