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1310713127147 is a prime number
BaseRepresentation
bin10011000100101100100…
…101110010000011101011
311122022011211222200220002
4103010230211302003223
5132433320030032042
62442044443053215
7163460456520254
oct23045445620353
94568154880802
101310713127147
11465963432186
1219203721120b
13967a476c028
1447620301b2b
15241646ea132
hex1312c9720eb

1310713127147 has 2 divisors, whose sum is σ = 1310713127148. Its totient is φ = 1310713127146.

The previous prime is 1310713127093. The next prime is 1310713127161. The reversal of 1310713127147 is 7417213170131.

It is a happy number.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 1310713127147 - 210 = 1310713126123 is a prime.

It is a super-3 number, since 3×13107131271473 (a number of 37 digits) contains 333 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 1310713127147.

It is not a weakly prime, because it can be changed into another prime (1310713127447) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655356563573 + 655356563574.

It is an arithmetic number, because the mean of its divisors is an integer number (655356563574).

Almost surely, 21310713127147 is an apocalyptic number.

1310713127147 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310713127147 is an equidigital number, since it uses as much as digits as its factorization.

1310713127147 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 24696, while the sum is 38.

Adding to 1310713127147 its reverse (7417213170131), we get a palindrome (8727926297278).

The spelling of 1310713127147 in words is "one trillion, three hundred ten billion, seven hundred thirteen million, one hundred twenty-seven thousand, one hundred forty-seven".