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1310782841129 is a prime number
BaseRepresentation
bin10011000100110000101…
…111101110000100101001
311122022100201011112111102
4103010300233232010221
5132433440401404004
62442055413211145
7163462264213106
oct23046057560451
94568321145442
101310782841129
11465999818343
12192056630ab5
13967b603a5c8
144762968baad
152416a8bb11e
hex13130bee129

1310782841129 has 2 divisors, whose sum is σ = 1310782841130. Its totient is φ = 1310782841128.

The previous prime is 1310782841089. The next prime is 1310782841131. The reversal of 1310782841129 is 9211482870131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1307260656025 + 3522185104 = 1143355^2 + 59348^2 .

It is a cyclic number.

It is not a de Polignac number, because 1310782841129 - 236 = 1242063364393 is a prime.

Together with 1310782841131, it forms a pair of twin primes.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (1310782841029) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655391420564 + 655391420565.

It is an arithmetic number, because the mean of its divisors is an integer number (655391420565).

Almost surely, 21310782841129 is an apocalyptic number.

It is an amenable number.

1310782841129 is a deficient number, since it is larger than the sum of its proper divisors (1).

1310782841129 is an equidigital number, since it uses as much as digits as its factorization.

1310782841129 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 193536, while the sum is 47.

The spelling of 1310782841129 in words is "one trillion, three hundred ten billion, seven hundred eighty-two million, eight hundred forty-one thousand, one hundred twenty-nine".