Base | Representation |
---|---|
bin | 111101000010100011… |
… | …1111100000101111111 |
3 | 110112100100210101222101 |
4 | 1322011013330011333 |
5 | 4121424103013014 |
6 | 140115104125531 |
7 | 12320226415603 |
oct | 1720507740577 |
9 | 415310711871 |
10 | 131082469759 |
11 | 5065670073a |
12 | 214a33068a7 |
13 | c490228297 |
14 | 64b7163503 |
15 | 3622dd5474 |
hex | 1e851fc17f |
131082469759 has 2 divisors, whose sum is σ = 131082469760. Its totient is φ = 131082469758.
The previous prime is 131082469691. The next prime is 131082469781. The reversal of 131082469759 is 957964280131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131082469759 - 221 = 131080372607 is a prime.
It is a super-2 number, since 2×1310824697592 (a number of 23 digits) contains 22 as substring.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131082460759) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65541234879 + 65541234880.
It is an arithmetic number, because the mean of its divisors is an integer number (65541234880).
It is a 1-persistent number, because it is pandigital, but 2⋅131082469759 = 262164939518 is not.
Almost surely, 2131082469759 is an apocalyptic number.
131082469759 is a deficient number, since it is larger than the sum of its proper divisors (1).
131082469759 is an equidigital number, since it uses as much as digits as its factorization.
131082469759 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 3265920, while the sum is 55.
The spelling of 131082469759 in words is "one hundred thirty-one billion, eighty-two million, four hundred sixty-nine thousand, seven hundred fifty-nine".
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