13110000193 has 2 divisors, whose sum is σ = 13110000194. Its totient is φ = 13110000192.

The previous prime is 13110000191. The next prime is 13110000221. The reversal of 13110000193 is 39100001131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12662550784 + 447449409 = 112528^2 + 21153^2 .

It is an emirp because it is prime and its reverse (39100001131) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 13110000193 - 2¹ = 13110000191 is a prime.

Together with 13110000191, it forms a pair of twin primes.

It is a self number, because there is not a number n which added to its sum of digits gives 13110000193.

It is not a weakly prime, because it can be changed into another prime (13110000191) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555000096 + 6555000097.

It is an arithmetic number, because the mean of its divisors is an integer number (6555000097).

Almost surely, 2^13110000193 is an apocalyptic number.

It is an amenable number.

13110000193 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110000193 is an equidigital number, since it uses as much as digits as its factorization.

13110000193 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 81, while the sum is 19.

The spelling of 13110000193 in words is "thirteen billion, one hundred ten million, one hundred ninety-three", and thus it is an aban number.