Base | Representation |
---|---|
bin | 11101110011110000011010… |
… | …010011110000100001110110 |
3 | 122012012001002000121012012202 |
4 | 131303300122103300201312 |
5 | 114140420321410131410 |
6 | 1142454304051144502 |
7 | 36420443534063210 |
oct | 3563603223604166 |
9 | 565161060535182 |
10 | 131100023130230 |
11 | 38855231317310 |
12 | 128540905a5132 |
13 | 581c8aa09b58b |
14 | 24533bc7675b0 |
15 | 102532c0b7ca5 |
hex | 773c1a4f0876 |
131100023130230 has 64 divisors (see below), whose sum is σ = 294334029158400. Its totient is φ = 40844963472000.
The previous prime is 131100023130229. The next prime is 131100023130247. The reversal of 131100023130230 is 32031320001131.
It is a super-3 number, since 3×1311000231302303 (a number of 43 digits) contains 333 as substring.
It is a Curzon number.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 34399805 + ... + 38020344.
It is an arithmetic number, because the mean of its divisors is an integer number (4598969205600).
Almost surely, 2131100023130230 is an apocalyptic number.
131100023130230 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
131100023130230 is an abundant number, since it is smaller than the sum of its proper divisors (163234006028170).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131100023130230 is a wasteful number, since it uses less digits than its factorization.
131100023130230 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 72422525.
The product of its (nonzero) digits is 324, while the sum is 20.
Adding to 131100023130230 its reverse (32031320001131), we get a palindrome (163131343131361).
The spelling of 131100023130230 in words is "one hundred thirty-one trillion, one hundred billion, twenty-three million, one hundred thirty thousand, two hundred thirty".
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