Base | Representation |
---|---|
bin | 10011000100111101110… |
… | …010011111111010111111 |
3 | 11122022220221221100221121 |
4 | 103010331302133322333 |
5 | 132434412412022112 |
6 | 2442133231411411 |
7 | 163500562234066 |
oct | 23047562377277 |
9 | 4568827840847 |
10 | 1311001673407 |
11 | 465aa12a3268 |
12 | 1920b7983b67 |
13 | 9681c48966a |
14 | 4764a7731dd |
15 | 2417ebe5407 |
hex | 1313dc9febf |
1311001673407 has 2 divisors, whose sum is σ = 1311001673408. Its totient is φ = 1311001673406.
The previous prime is 1311001673363. The next prime is 1311001673431. The reversal of 1311001673407 is 7043761001131.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1311001673407 is a prime.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (1311001673467) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655500836703 + 655500836704.
It is an arithmetic number, because the mean of its divisors is an integer number (655500836704).
Almost surely, 21311001673407 is an apocalyptic number.
1311001673407 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311001673407 is an equidigital number, since it uses as much as digits as its factorization.
1311001673407 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 10584, while the sum is 34.
Adding to 1311001673407 its reverse (7043761001131), we get a palindrome (8354762674538).
The spelling of 1311001673407 in words is "one trillion, three hundred eleven billion, one million, six hundred seventy-three thousand, four hundred seven".
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