13110100041431 has 2 divisors, whose sum is σ = 13110100041432. Its totient is φ = 13110100041430.

The previous prime is 13110100041413. The next prime is 13110100041433. The reversal of 13110100041431 is 13414000101131.

Together with previous prime (13110100041413) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13110100041431 - 2³⁴ = 13092920172247 is a prime.

It is a super-2 number, since 2×13110100041431² (a number of 27 digits) contains 22 as substring.

Together with 13110100041433, it forms a pair of twin primes.

It is a Chen prime.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13110100041433) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555050020715 + 6555050020716.

It is an arithmetic number, because the mean of its divisors is an integer number (6555050020716).

Almost surely, 2^{13110100041431} is an apocalyptic number.

13110100041431 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110100041431 is an equidigital number, since it uses as much as digits as its factorization.

13110100041431 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13110100041431 its reverse (13414000101131), we get a palindrome (26524100142562).

The spelling of 13110100041431 in words is "thirteen trillion, one hundred ten billion, one hundred million, forty-one thousand, four hundred thirty-one".