131101004014327 has 2 divisors, whose sum is σ = 131101004014328. Its totient is φ = 131101004014326.

The previous prime is 131101004014319. The next prime is 131101004014349. The reversal of 131101004014327 is 723410400101131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131101004014327 - 2³ = 131101004014319 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 131101004014295 and 131101004014304.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131101004014727) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550502007163 + 65550502007164.

It is an arithmetic number, because the mean of its divisors is an integer number (65550502007164).

Almost surely, 2^{131101004014327} is an apocalyptic number.

131101004014327 is a deficient number, since it is larger than the sum of its proper divisors (1).

131101004014327 is an equidigital number, since it uses as much as digits as its factorization.

131101004014327 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 2016, while the sum is 28.

Adding to 131101004014327 its reverse (723410400101131), we get a palindrome (854511404115458).

The spelling of 131101004014327 in words is "one hundred thirty-one trillion, one hundred one billion, four million, fourteen thousand, three hundred twenty-seven".