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131101004014349 is a prime number
BaseRepresentation
bin11101110011110001010100…
…110001100010001100001101
3122012012010121101022021021012
4131303301110301202030031
5114140424324011424344
61142454545251015005
736420510044336525
oct3563612461421415
9565163541267235
10131101004014349
1138855694a74046
1212854304b9a465
13581ca05374895
142453472b3a685
15102538827029e
hex773c54c6230d

131101004014349 has 2 divisors, whose sum is σ = 131101004014350. Its totient is φ = 131101004014348.

The previous prime is 131101004014327. The next prime is 131101004014369. The reversal of 131101004014349 is 943410400101131.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 129669348690025 + 1431655324324 = 11387245^2 + 1196518^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131101004014349 is a prime.

It is a super-2 number, since 2×1311010040143492 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131101004014319) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550502007174 + 65550502007175.

It is an arithmetic number, because the mean of its divisors is an integer number (65550502007175).

Almost surely, 2131101004014349 is an apocalyptic number.

It is an amenable number.

131101004014349 is a deficient number, since it is larger than the sum of its proper divisors (1).

131101004014349 is an equidigital number, since it uses as much as digits as its factorization.

131101004014349 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 5184, while the sum is 32.

The spelling of 131101004014349 in words is "one hundred thirty-one trillion, one hundred one billion, four million, fourteen thousand, three hundred forty-nine".