13110110327 has 2 divisors, whose sum is σ = 13110110328. Its totient is φ = 13110110326.

The previous prime is 13110110317. The next prime is 13110110329. The reversal of 13110110327 is 72301101131.

It is a strong prime.

It is a cyclic number.

It is not a de Polignac number, because 13110110327 - 2¹² = 13110106231 is a prime.

It is a super-2 number, since 2×13110110327² (a number of 21 digits) contains 22 as substring.

Together with 13110110329, it forms a pair of twin primes.

It is a Chen prime.

It is a junction number, because it is equal to n+sod(n) for n = 13110110299 and 13110110308.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (13110110329) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555055163 + 6555055164.

It is an arithmetic number, because the mean of its divisors is an integer number (6555055164).

Almost surely, 2^13110110327 is an apocalyptic number.

13110110327 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110110327 is an equidigital number, since it uses as much as digits as its factorization.

13110110327 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 126, while the sum is 20.

Adding to 13110110327 its reverse (72301101131), we get a palindrome (85411211458).

The spelling of 13110110327 in words is "thirteen billion, one hundred ten million, one hundred ten thousand, three hundred twenty-seven".