Base | Representation |
---|---|
bin | 1011111011000110111110… |
… | …0100110001111111101001 |
3 | 1201102022111020211210101121 |
4 | 2332301233210301333221 |
5 | 3204244002144202304 |
6 | 43514411413015241 |
7 | 2522113541122066 |
oct | 276615744617751 |
9 | 51368436753347 |
10 | 13110112100329 |
11 | 41a4a70556502 |
12 | 15789b2024521 |
13 | 74138047467a |
14 | 334766069c6d |
15 | 17b056524554 |
hex | bec6f931fe9 |
13110112100329 has 2 divisors, whose sum is σ = 13110112100330. Its totient is φ = 13110112100328.
The previous prime is 13110112100269. The next prime is 13110112100347. The reversal of 13110112100329 is 92300121101131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 8489968200025 + 4620143900304 = 2913755^2 + 2149452^2 .
It is an emirp because it is prime and its reverse (92300121101131) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 13110112100329 - 215 = 13110112067561 is a prime.
It is not a weakly prime, because it can be changed into another prime (13110112100389) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555056050164 + 6555056050165.
It is an arithmetic number, because the mean of its divisors is an integer number (6555056050165).
Almost surely, 213110112100329 is an apocalyptic number.
It is an amenable number.
13110112100329 is a deficient number, since it is larger than the sum of its proper divisors (1).
13110112100329 is an equidigital number, since it uses as much as digits as its factorization.
13110112100329 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 324, while the sum is 25.
The spelling of 13110112100329 in words is "thirteen trillion, one hundred ten billion, one hundred twelve million, one hundred thousand, three hundred twenty-nine".
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