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13110112100347 is a prime number
BaseRepresentation
bin1011111011000110111110…
…0100110001111111111011
31201102022111020211210102021
42332301233210301333323
53204244002144202342
643514411413015311
72522113541122123
oct276615744617773
951368436753367
1013110112100347
1141a4a70556519
1215789b2024537
13741380474692
14334766069c83
1517b056524567
hexbec6f931ffb

13110112100347 has 2 divisors, whose sum is σ = 13110112100348. Its totient is φ = 13110112100346.

The previous prime is 13110112100329. The next prime is 13110112100389. The reversal of 13110112100347 is 74300121101131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 13110112100347 - 27 = 13110112100219 is a prime.

It is not a weakly prime, because it can be changed into another prime (13110112100747) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6555056050173 + 6555056050174.

It is an arithmetic number, because the mean of its divisors is an integer number (6555056050174).

Almost surely, 213110112100347 is an apocalyptic number.

13110112100347 is a deficient number, since it is larger than the sum of its proper divisors (1).

13110112100347 is an equidigital number, since it uses as much as digits as its factorization.

13110112100347 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 25.

Adding to 13110112100347 its reverse (74300121101131), we get a palindrome (87410233201478).

The spelling of 13110112100347 in words is "thirteen trillion, one hundred ten billion, one hundred twelve million, one hundred thousand, three hundred forty-seven".