131101220023 has 2 divisors, whose sum is σ = 131101220024. Its totient is φ = 131101220022.

The previous prime is 131101220021. The next prime is 131101220027. The reversal of 131101220023 is 320022101131.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 131101220023 - 2¹ = 131101220021 is a prime.

It is a super-2 number, since 2×131101220023² (a number of 23 digits) contains 22 as substring.

Together with 131101220021, it forms a pair of twin primes.

It is a junction number, because it is equal to n+sod(n) for n = 131101219979 and 131101220006.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131101220021) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (23) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550610011 + 65550610012.

It is an arithmetic number, because the mean of its divisors is an integer number (65550610012).

Almost surely, 2^131101220023 is an apocalyptic number.

131101220023 is a deficient number, since it is larger than the sum of its proper divisors (1).

131101220023 is an equidigital number, since it uses as much as digits as its factorization.

131101220023 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 72, while the sum is 16.

Adding to 131101220023 its reverse (320022101131), we get a palindrome (451123321154).

The spelling of 131101220023 in words is "one hundred thirty-one billion, one hundred one million, two hundred twenty thousand, twenty-three".