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13110122432140 = 225655506121607
BaseRepresentation
bin1011111011000111000000…
…1100001100011010001100
31201102022111222021200222021
42332301300030030122030
53204244012320312030
643514412422255524
72522114025003016
oct276616014143214
951368458250867
1013110122432140
1141a4a76372998
1215789b55875a4
13741382651276
143347675991b6
1517b0573b597a
hexbec7030c68c

13110122432140 has 12 divisors (see below), whose sum is σ = 27531257107536. Its totient is φ = 5244048972848.

The previous prime is 13110122432129. The next prime is 13110122432203. The reversal of 13110122432140 is 4123422101131.

It is an unprimeable number.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 327753060784 + ... + 327753060823.

It is an arithmetic number, because the mean of its divisors is an integer number (2294271425628).

Almost surely, 213110122432140 is an apocalyptic number.

13110122432140 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

13110122432140 is an abundant number, since it is smaller than the sum of its proper divisors (14421134675396).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110122432140 is a wasteful number, since it uses less digits than its factorization.

13110122432140 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 655506121616 (or 655506121614 counting only the distinct ones).

The product of its (nonzero) digits is 1152, while the sum is 25.

Adding to 13110122432140 its reverse (4123422101131), we get a palindrome (17233544533271).

The spelling of 13110122432140 in words is "thirteen trillion, one hundred ten billion, one hundred twenty-two million, four hundred thirty-two thousand, one hundred forty".

Divisors: 1 2 4 5 10 20 655506121607 1311012243214 2622024486428 3277530608035 6555061216070 13110122432140