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131101232041019 is a prime number
BaseRepresentation
bin11101110011110001100010…
…010111011000110000111011
3122012012011012021101020001102
4131303301202113120300323
5114140430310400303034
61142455024034242015
736420515513463362
oct3563614227306073
9565164167336042
10131101232041019
11388557a1759939
121285436942630b
13581ca406928c6
1424534951367d9
15102539d2b397e
hex773c625d8c3b

131101232041019 has 2 divisors, whose sum is σ = 131101232041020. Its totient is φ = 131101232041018.

The previous prime is 131101232040971. The next prime is 131101232041067. The reversal of 131101232041019 is 910140232101131.

It is a happy number.

It is a balanced prime because it is at equal distance from previous prime (131101232040971) and next prime (131101232041067).

It is a cyclic number.

It is not a de Polignac number, because 131101232041019 - 232 = 131096937073723 is a prime.

It is a super-2 number, since 2×1311012320410192 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 131101232040982 and 131101232041000.

It is not a weakly prime, because it can be changed into another prime (131101232091019) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550616020509 + 65550616020510.

It is an arithmetic number, because the mean of its divisors is an integer number (65550616020510).

Almost surely, 2131101232041019 is an apocalyptic number.

131101232041019 is a deficient number, since it is larger than the sum of its proper divisors (1).

131101232041019 is an equidigital number, since it uses as much as digits as its factorization.

131101232041019 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1296, while the sum is 29.

The spelling of 131101232041019 in words is "one hundred thirty-one trillion, one hundred one billion, two hundred thirty-two million, forty-one thousand, nineteen".