Base | Representation |
---|---|
bin | 11101110011110001100010… |
… | …010111011000110110110111 |
3 | 122012012011012021101020120111 |
4 | 131303301202113120312313 |
5 | 114140430310400311044 |
6 | 1142455024034243451 |
7 | 36420515513464444 |
oct | 3563614227306667 |
9 | 565164167336514 |
10 | 131101232041399 |
11 | 388557a175a154 |
12 | 12854369426587 |
13 | 581ca40692b29 |
14 | 24534951369cb |
15 | 102539d2b3b34 |
hex | 773c625d8db7 |
131101232041399 has 2 divisors, whose sum is σ = 131101232041400. Its totient is φ = 131101232041398.
The previous prime is 131101232041397. The next prime is 131101232041459. The reversal of 131101232041399 is 993140232101131.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 131101232041399 - 21 = 131101232041397 is a prime.
Together with 131101232041397, it forms a pair of twin primes.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (131101232041397) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550616020699 + 65550616020700.
It is an arithmetic number, because the mean of its divisors is an integer number (65550616020700).
Almost surely, 2131101232041399 is an apocalyptic number.
131101232041399 is a deficient number, since it is larger than the sum of its proper divisors (1).
131101232041399 is an equidigital number, since it uses as much as digits as its factorization.
131101232041399 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 34992, while the sum is 40.
The spelling of 131101232041399 in words is "one hundred thirty-one trillion, one hundred one billion, two hundred thirty-two million, forty-one thousand, three hundred ninety-nine".
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