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131101314244423 is a prime number
BaseRepresentation
bin11101110011110001100111…
…010000111101111101000111
3122012012011102000001120220221
4131303301213100331331013
5114140430442421310143
61142455040132205211
736420520532264425
oct3563614720757507
9565164360046827
10131101314244423
11388558340a5536
1212854390a69807
13581ca54714b83
1424534a2014115
1510253a56002ed
hex773c6743df47

131101314244423 has 2 divisors, whose sum is σ = 131101314244424. Its totient is φ = 131101314244422.

The previous prime is 131101314244393. The next prime is 131101314244471. The reversal of 131101314244423 is 324442413101131.

It is a weak prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-131101314244423 is a prime.

It is a super-2 number, since 2×1311013142444232 (a number of 29 digits) contains 22 as substring.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (131101314244723) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (29) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65550657122211 + 65550657122212.

It is an arithmetic number, because the mean of its divisors is an integer number (65550657122212).

Almost surely, 2131101314244423 is an apocalyptic number.

131101314244423 is a deficient number, since it is larger than the sum of its proper divisors (1).

131101314244423 is an equidigital number, since it uses as much as digits as its factorization.

131101314244423 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 27648, while the sum is 34.

Adding to 131101314244423 its reverse (324442413101131), we get a palindrome (455543727345554).

The spelling of 131101314244423 in words is "one hundred thirty-one trillion, one hundred one billion, three hundred fourteen million, two hundred forty-four thousand, four hundred twenty-three".