Base | Representation |
---|---|
bin | 11101110011110010010000… |
… | …110000001101011001101011 |
3 | 122012012020012111210212200112 |
4 | 131303302100300031121223 |
5 | 114140433404114100021 |
6 | 1142455233155124535 |
7 | 36420544013540132 |
oct | 3563622060153153 |
9 | 565166174725615 |
10 | 131102010300011 |
11 | 38856060aa0393 |
12 | 12854545ba374b |
13 | 581cb359a2a9a |
14 | 245352a642919 |
15 | 10253e6793d5b |
hex | 773c90c0d66b |
131102010300011 has 2 divisors, whose sum is σ = 131102010300012. Its totient is φ = 131102010300010.
The previous prime is 131102010299989. The next prime is 131102010300013. The reversal of 131102010300011 is 110003010201131.
It is a happy number.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 131102010300011 - 214 = 131102010283627 is a prime.
Together with 131102010300013, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (131102010300013) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 65551005150005 + 65551005150006.
It is an arithmetic number, because the mean of its divisors is an integer number (65551005150006).
Almost surely, 2131102010300011 is an apocalyptic number.
131102010300011 is a deficient number, since it is larger than the sum of its proper divisors (1).
131102010300011 is an equidigital number, since it uses as much as digits as its factorization.
131102010300011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 18, while the sum is 14.
Adding to 131102010300011 its reverse (110003010201131), we get a palindrome (241105020501142).
The spelling of 131102010300011 in words is "one hundred thirty-one trillion, one hundred two billion, ten million, three hundred thousand, eleven".
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