Base | Representation |
---|---|
bin | 10011000100111111000… |
… | …000011110001010101001 |
3 | 11122022222101101211102012 |
4 | 103010333000132022221 |
5 | 132434433130112244 |
6 | 2442135241445305 |
7 | 163501231045046 |
oct | 23047700361251 |
9 | 4568871354365 |
10 | 1311022113449 |
11 | 466001894164 |
12 | 1921027a0835 |
13 | 96823795169 |
14 | 4764d3741cd |
15 | 241818d189e |
hex | 1313f01e2a9 |
1311022113449 has 2 divisors, whose sum is σ = 1311022113450. Its totient is φ = 1311022113448.
The previous prime is 1311022113403. The next prime is 1311022113451. The reversal of 1311022113449 is 9443112201131.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 948218275225 + 362803838224 = 973765^2 + 602332^2 .
It is a cyclic number.
It is not a de Polignac number, because 1311022113449 - 240 = 211510485673 is a prime.
Together with 1311022113451, it forms a pair of twin primes.
It is a Chen prime.
It is not a weakly prime, because it can be changed into another prime (1311022116449) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655511056724 + 655511056725.
It is an arithmetic number, because the mean of its divisors is an integer number (655511056725).
Almost surely, 21311022113449 is an apocalyptic number.
It is an amenable number.
1311022113449 is a deficient number, since it is larger than the sum of its proper divisors (1).
1311022113449 is an equidigital number, since it uses as much as digits as its factorization.
1311022113449 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 5184, while the sum is 32.
The spelling of 1311022113449 in words is "one trillion, three hundred eleven billion, twenty-two million, one hundred thirteen thousand, four hundred forty-nine".
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