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1311032353 is a prime number
BaseRepresentation
bin100111000100100…
…1100010000100001
310101100221100021211
41032021030100201
510141111013403
6334031550121
744326406521
oct11611142041
93340840254
101311032353
11613053014
1230708b341
1317b7cb6b7
14c6193681
157a16e06d
hex4e24c421

1311032353 has 2 divisors, whose sum is σ = 1311032354. Its totient is φ = 1311032352.

The previous prime is 1311032351. The next prime is 1311032381. The reversal of 1311032353 is 3532301131.

It is a happy number.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1282857489 + 28174864 = 35817^2 + 5308^2 .

It is a cyclic number.

It is not a de Polignac number, because 1311032353 - 21 = 1311032351 is a prime.

It is a super-2 number, since 2×13110323532 = 3437611661225433218, which contains 22 as substring.

Together with 1311032351, it forms a pair of twin primes.

It is not a weakly prime, because it can be changed into another prime (1311032351) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (11) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 655516176 + 655516177.

It is an arithmetic number, because the mean of its divisors is an integer number (655516177).

Almost surely, 21311032353 is an apocalyptic number.

It is an amenable number.

1311032353 is a deficient number, since it is larger than the sum of its proper divisors (1).

1311032353 is an equidigital number, since it uses as much as digits as its factorization.

1311032353 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 810, while the sum is 22.

The square root of 1311032353 is about 36208.1807468975. The cubic root of 1311032353 is about 1094.4715319302.

Adding to 1311032353 its reverse (3532301131), we get a palindrome (4843333484).

The spelling of 1311032353 in words is "one billion, three hundred eleven million, thirty-two thousand, three hundred fifty-three".