Base | Representation |
---|---|
bin | 111101000011001011… |
… | …1110011000111010100 |
3 | 110112101211012000001011 |
4 | 1322012113303013110 |
5 | 4121444432421000 |
6 | 140121132542004 |
7 | 12320602360045 |
oct | 1720627630724 |
9 | 415354160034 |
10 | 131103404500 |
11 | 506674aa282 |
12 | 214aa321904 |
13 | c494677cc3 |
14 | 64b9c528cc |
15 | 3624b6d2ba |
hex | 1e865f31d4 |
131103404500 has 48 divisors (see below), whose sum is σ = 286365538368. Its totient is φ = 52434823200.
The previous prime is 131103404491. The next prime is 131103404501. The reversal of 131103404500 is 5404301131.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (131103404501) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 7044207 + ... + 7062793.
It is an arithmetic number, because the mean of its divisors is an integer number (5965948716).
Almost surely, 2131103404500 is an apocalyptic number.
131103404500 is a gapful number since it is divisible by the number (10) formed by its first and last digit.
It is an amenable number.
131103404500 is an abundant number, since it is smaller than the sum of its proper divisors (155262133868).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
131103404500 is a wasteful number, since it uses less digits than its factorization.
131103404500 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 32713 (or 32701 counting only the distinct ones).
The product of its (nonzero) digits is 720, while the sum is 22.
Adding to 131103404500 its reverse (5404301131), we get a palindrome (136507705631).
The spelling of 131103404500 in words is "one hundred thirty-one billion, one hundred three million, four hundred four thousand, five hundred".
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