13110401131400 has 96 divisors (see below), whose sum is σ = 30750774012000. Its totient is φ = 5197987576320.

The previous prime is 13110401131397. The next prime is 13110401131411. The reversal of 13110401131400 is 413110401131.

It is a Harshad number since it is a multiple of its sum of digits (20).

It is an unprimeable number.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 16770431 + ... + 17534769.

It is an arithmetic number, because the mean of its divisors is an integer number (320320562625).

Almost surely, 2^{13110401131400} is an apocalyptic number.

13110401131400 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 13110401131400, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (15375387006000).

13110401131400 is an abundant number, since it is smaller than the sum of its proper divisors (17640372880600).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

13110401131400 is a wasteful number, since it uses less digits than its factorization.

13110401131400 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 765111 (or 765102 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 13110401131400 its reverse (413110401131), we get a palindrome (13523511532531).

The spelling of 13110401131400 in words is "thirteen trillion, one hundred ten billion, four hundred one million, one hundred thirty-one thousand, four hundred".